“…In fact, it is probable that the only change in the donors is that they are more likely to be close to acceptors, because of the high N concentration, and thus will contribute to emission through a D 0 A 0 process, rather than an excitonic process. The position of the A 0 X line in the N-doped sample is a little below that in the undoped sample, but, interestingly, this is exactly what is seen in both ZnSe and ZnS doped with N. 21 The broad line centered at 3.238 eV in the N-doped sample is probably composed of two emissions: ͑1͒ an LOphonon replica of A 0 X and ͑2͒ D 0 A 0 recombination. The D 0 A 0 energy for a given pair will be given by E DA ϭE G ϪE D ϪE A ϩe 2 /4 r, where E G , E D , and E A are the band gap, donor, and acceptor energies, respectively, is the dielectric constant, and r is the pair separation.…”