“…Assuming 1/5 of the phase (or overall settling time to be allocated for slewing, while the remaining 4/5 for linear settling , for the worst-case estimation, the OTA must be capable to drive the equivalent total capacitive loading to a certain output voltage step during the slewing time interval , and also be exponentially settled within 0.1% accuracy during the slewing interval (the closed-loop time constant is approximately /7). Thus, the required tail bias current of the OTA can be simply estimated as (17) where and are the tail current required in slewing and linear settling time intervals, respectively, and can be given by Therefore, the expected static power of the OTA is given by the product of the supply voltage and the , i.e., . It is worth pointing out that a final optimum solution of the tail current normally needs to be investigated according to the required specifications in terms of gain, speed, power, dynamic range, and noise, as well as with a necessary safety margin for counting the process parasitics and variations.…”