1985
DOI: 10.1063/1.335610
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The doping concentration dependence of the zinc acceptor ionization energy in In0.49Ga0.51P

Abstract: The doping concentration dependence of the zinc acceptor energy level in In0.49Ga0.51P has been studied and can be expressed as EA=45.75−8.20×10−6 P1/3 meV, where P is the zinc acceptor concentration in cm−3. The zinc-doped In0.49Ga0.51P epitaxial layers were grown on 〈100〉 oriented semi-insulating GaAs substrates which are in very good crystallinity with a lattice mismatch of only 0.26%.

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Cited by 12 publications
(3 citation statements)
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“…Note that the depth of acceptor level, ΔE A , depends on the ionized acceptor concentration owing to the Coulomb potential of ionized acceptors. ΔE A is expressed as [18][19][20])…”
Section: Regular Papermentioning
confidence: 99%
“…Note that the depth of acceptor level, ΔE A , depends on the ionized acceptor concentration owing to the Coulomb potential of ionized acceptors. ΔE A is expressed as [18][19][20])…”
Section: Regular Papermentioning
confidence: 99%
“…26 In a simple model, the reduction of the ionization energy is assumed to be inversely proportional to the average distance between the Al acceptors. This simple relation can be represented by the following expression: [26][27][28]…”
Section: B Ionization Ratio and Ionization Energy Of Acceptorsmentioning
confidence: 99%
“…where p is the hole concentration in the p-emitter, µ p is the hole mobility in the p-emitter, d is the emitter thickness, l is the digit length and x is the width of the part of the photoactive area. Due to a relatively large ionization energy of Mg acceptors in GaInP (being equal to 39.7 meV for the doping level of 4 × 10 17 according to [27]) the hole concentration depends on the temperature in the wide range as shown in figure 13, where p is calculated using Fermi-Dirac statistics. Assuming linear temperature dependence of the hole mobility (from 100 cm 2 s −1 V −1 at 100 K to 50 cm 2 s −1 V −1 at 300 K) and using geometrical parameters of the solar cell grid the equivalent capacitance of the circuit presented in figure 12 was calculated.…”
Section: Discussionmentioning
confidence: 99%